Factoring Binomials - Cubes #2

Описание к видео Factoring Binomials - Cubes #2

Factoring the difference and sum of cubes #2.

PLEASE NOTE: While the technique for factoring the difference of cubes with a lead coefficient other than one shown in this video is correct, this is not the best example. In choosing the example, I failed to consider that 64 and 8 have a common factor of 8 that could have been factored out first leaving the difference of cubes with a lead coefficient of one to factor (an easier problem!). This can still be done at the end of the factoring shown here to complete the problem by factoring the common factor of 2 out of the binomial part of the answer and a 4 out of the trinomial part, multiplying 2 and 4 together and putting the answer (8) in front. The completely factored answer would then be: 8(x - 2)(x^2 + 2x + 4). Without doing this, the binomial cube would not be factored completely! Please refer to the newer video entitled: Factoring Binomials - Cubes Lead Coefficient Other Than 1 HD for a better example!

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