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Скачать или смотреть Resolving the IsADirectoryError in Python: Copying Files Hassle-Free

  • vlogize
  • 2025-08-16
  • 1
Resolving the IsADirectoryError in Python: Copying Files Hassle-Free
IsADirectoryError: [Errno 21] Is a directory: '/' while copying files from one folder to another exipythonpython 3.x
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Encountering the `IsADirectoryError` while copying files in Python? Discover how to fix the issue effectively and enhance your file management skills with easy-to-follow code corrections.
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This video is based on the question https://stackoverflow.com/q/64815226/ asked by the user 'tangybbq' ( https://stackoverflow.com/u/14089685/ ) and on the answer https://stackoverflow.com/a/64839201/ provided by the user 'tdelaney' ( https://stackoverflow.com/u/642070/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: IsADirectoryError: [Errno 21] Is a directory: '/' while copying files from one folder to another existing folder Python

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Understanding the IsADirectoryError in Python

Are you facing an IsADirectoryError while attempting to copy files from one folder to another using Python? If you're building a basic file manager program as part of your learning journey, you've likely encountered this frustrating error:
IsADirectoryError: [Errno 21] Is a directory: '/'

This error typically indicates that the program is trying to treat a directory as a file. In this post, we'll explore the root cause of this issue and how you can fix it effectively, ensuring smooth file operations in your Python applications.

The Problem: What’s Causing the Error?

The error arises from your code's handling of directories and files. Specifically, the function singulateDataInDir is not yielding file names as expected; instead, it returns a single path. Consequently, when you attempt to iterate over this result, the loop retrieves characters from the returned string rather than actual file names, which leads to confusion and the subsequent error message.

For instance, here's the problematic part of your code:

[[See Video to Reveal this Text or Code Snippet]]

This line is trying to iterate over a string containing just the path, beginning with "/".

The Solution: Code Modifications to Fix the Error

To resolve this issue, you need to modify the singulateDataInDir function to yield file names instead of returning them. This adjustment will allow you to properly iterate over the files in the source directory.

Step 1: Update the singulateDataInDir Function

Here’s the corrected version of the function:

[[See Video to Reveal this Text or Code Snippet]]

Key Changes:

Use yield instead of return: This allows the function to produce an iterable sequence of file paths.

Adjust the default parameters: Change the initial values of passBackFiles and passBackDirs to False instead of using bool, which is a type object, and doesn't serve the intended purpose here.

Step 2: Ensure Proper Calls in the copyFilesFromSRCtoDEST Function

Now that we have updated singulateDataInDir, your copying function may remain the same. Ensure it looks like this:

[[See Video to Reveal this Text or Code Snippet]]

This will effectively copy all files from the source directory to the desired destination without running into the directory error.

Conclusion

By ensuring your function yields file names rather than returning a single path, you seamlessly avoid the IsADirectoryError you were encountering. The adjustments outlined in this post will help you develop a better understanding of file handling in Python while enhancing your skill set as you build your file manager.

If you have any further questions or need assistance with your Python projects, feel free to reach out. Happy coding!

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