Скачать или смотреть Ex 6.3 Q7 Class 10 Triangles | Altitudes AD & CE meet at P — Prove 4 Similarities | NCERT Maths

In this video we solve Exercise 6.3 — Question 7th from Class 10 Maths (NCERT), Chapter 6 — Triangles, step-by-step using angle-chasing and similarity criteria.

🎯 Question (NCERT):
In Fig. 6.38, altitudes AD and CE of ΔABC intersect each other at point P. Show that:
(i) ΔAEP ~ ΔCDP
(ii) ΔABD ~ ΔCBE
(iii) ΔAEP ~ ΔADB
(iv) ΔPDC ~ ΔBEC

✨ Approach:
Let’s go with a mathematical approach — use right-angle properties, corresponding angles, and the AA similarity criterion to prove each pair of similar triangles. Each part is explained with clear angle-chasing and diagram references so you can follow easily.

📝 What you’ll learn:


👉 How altitudes create right angles and corresponding angle pairs

👉 Applying AA (angle-angle) for triangle similarity

👉 Angle-chasing techniques for multi-part proofs

👉 How to convert geometric observation into formal proofs (useful for board exams)


🧮 Perfect for:

• Class 10 students, NCERT board exam preparation, quick revision before tests, and teachers creating lesson videos.