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Скачать или смотреть Polynomials – Class 9 Maths | Exercise 2.4 Part 1 Solutions | NCERT Class 9 Chapter 2.

  • Career With RajRatan
  • 2025-12-05
  • 0
Polynomials – Class 9 Maths | Exercise 2.4 Part 1 Solutions | NCERT Class 9 Chapter 2.
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Описание к видео Polynomials – Class 9 Maths | Exercise 2.4 Part 1 Solutions | NCERT Class 9 Chapter 2.

⭐ Welcome to Career With RajRatan! 🎓

In this video, we cover NCERT Class 9 Maths – Polynomials | Exercise 2.4 (Part 1) in the most simple and student-friendly way.

With crystal-clear board explanation ✏️, step-by-step solutions, and exam-oriented shortcuts, this session makes factorisation using identities extremely easy! 🔥

Perfect for students aiming for full marks in Algebra. ➗✨

🔍 What’s Included in Exercise 2.4 – Part 1

✔️ Factorisation using identities
✔️ Using cube identities:
 • (a – b)³ • (a + b)³
✔️ Quick tricks to evaluate numbers like 99³, 102³, 998³
✔️ Recognising expressions in the form of (x ± y)³
✔️ Step-by-step NCERT Question 7 & 8
✔️ Easy explanation + exam shortcuts 🎯

This session makes Exercise 2.4 (Part 1) super easy—perfect even for beginners! 😊📘

🕒 Timestamps

0:00 – 0:05
Hello everyone 👋, welcome to the platform of Career With RajRatan 🎓. I am Abhishek Sharma 😊.
0:05 – 0:09
And I will be teaching you Maths today ✏️📘. In the last class, we studied algebraic identities 📚—how they work and solved examples too ✔️. Now we will start Exercise 2.4, the last exercise of this chapter 💯.
0:24 – 0:28
Start with Question 1 🔢 — Use suitable identities to find the products.
Part 1: (x + 4)(x + 10)
Identity 🧠: (x + a)(x + b) = x² + (a + b)x + ab
a = 4, b = 10
Answer: x² + 14x + 40 ✨
Part 2: (x + 8)(x – 10)
Identity: (x + a)(x + b)
a = 8, b = –10
Answer: x² – 2x – 80 ✔️
Part 3: (3x + 4)(3x – 5)
Identity used with 3x ➕
Answer: 9x² – 3x – 20 🔹
Part 4: (y² + 3/2)(y² – 3/2)
Identity 🔄: (x + y)(x – y) = x² – y²
Answer: y⁴ – 9/4 ✔️
Part 5: (3 – 2x)(3 + 2x)
Identity: (x + y)(x – y)
Answer: 9 – 4x² ✨
Question 2 – Evaluate without direct multiplication 🧮
103 × 107
= 11121 🎉
95 × 96
= 9120 👍
104 × 96
= 9984 ✔️
Question 3 – Factorise using identities ✂️📘
9x² + 6xy + y²
= (3x + y)² 🌟
4y² – 4y + 1
= (2y – 1)² 🟩

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📚 Exercise-wise & chapter-wise solutions

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🔍 Keywords for High Ranking

Class 9 Maths Exercise 2.4 Part 1
NCERT Polynomials Class 9
Factorisation using identities Class 9
NCERT Solutions Exercise 2.4
Cube identities Class 9
Polynomials factorisation NCERT
Class 9 Algebra Chapter 2

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