Limit of sin(x)/x as x goes to Infinity (Squeeze Theorem) | Calculus 1 Exercises

We use the squeeze theorem to evaluate the limit of sinx/x as x approaches infinity. This is easy as soon as we recall -1 is less than or equal to sin(x) is less than or equal to 1, then just divide everything by x! #Calculus1

Limit of x*sin(1/x) as x approaches 0:    • Limit of x*sin(1/x) as x approaches 0...  
Limit of x*sin(1/x) as x approaches Infinity:    • Limit of x*sin(1/x) as x approaches I...  
Limit of sin(2x)/x as x approaches 0:    • Limit of sin(2x)/x as x approaches 0 ...  

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