Скачать или смотреть How to Create a Simple Java Login Page with Swing

Master the basics of creating a `Java` login page using Swing. Learn how to get input from text fields and validate credentials effectively.
---
This video is based on the question https://stackoverflow.com/q/63246065/ asked by the user 'Banana King' ( https://stackoverflow.com/u/10076831/ ) and on the answer https://stackoverflow.com/a/63246930/ provided by the user 'ggbond' ( https://stackoverflow.com/u/10056901/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Trying to make a login page, I am stuck! [java]

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
---
Building a Simple Java Login Page with Swing

Creating a login page is a fundamental task for many developers, especially those working with Java Swing. However, it's not uncommon to encounter challenges during the process, such as retrieving input from text fields and validating user credentials. In this post, we'll go through how to create a Java login page, focusing on ensuring that you can effectively capture and check user input.

The Challenge

In this scenario, you are attempting to implement a login feature in your Java Swing application. You want the program to verify the entered username and password when the login button is pressed. However, you've encountered an issue where the application skips directly to the "Access Denied" message, indicating that the input validation is not functioning as expected.

The Code Snippet

Here's a simplified version of the code you provided, highlighting the relevant parts related to user authentication:

[[See Video to Reveal this Text or Code Snippet]]

The Solution

To correctly handle the user input and validate the credentials, follow these steps:

1. Retrieving Input from Text Fields

To get the entered username and password, you need to use the getText() method on your text fields. Here's how to do it:

[[See Video to Reveal this Text or Code Snippet]]

2. Comparing Strings Correctly

Instead of using the == operator for string comparison (which compares object references), you should use the equals() method to compare the actual string contents. Here's how to modify your conditions:

[[See Video to Reveal this Text or Code Snippet]]

3. Updated actionPerformed Method

With the modifications above, your complete actionPerformed method now looks like this:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

By implementing these two key changes—correctly retrieving the username and password inputs and validating the inputs using equals()—you can successfully create a functional login page in Java Swing. This example encapsulates fundamental Java concepts that can be expanded upon as you develop more complex applications. Keep practicing and exploring, and soon you'll be able to build even more sophisticated login systems!

Do not hesitate to reach out if you have further questions or need additional clarifications regarding Java Swing GUI programming. Happy coding!