Скачать или смотреть R5 REAL NUMBERS Chapter-1 | Class 10th Mathematics | Product of two numbers equal to HCF*LCM|SSLC MS

Given numbers:
26 and 91
Step 1: Find the HCF (using prime factorization)
• 26 = 2 × 13
• 91 = 7 × 13
Common factor = 13
HCF = 13
Step 2: Find the LCM
LCM is the product of all prime factors (taking the highest power of each):
• 26 = 2 × 13
• 91 = 7 × 13
LCM = 2 × 7 × 13 = 182
Step 3: Verification: LCM × HCF = Product of the two numbers
• LCM × HCF = 182 × 13 = 2366
• Product of the numbers = 26 × 91 = 2366
Verified:
LCM × HCF = 26 × 91 = 2366


--------------------------------------------------------------------------------------------------------------------------------

#REALNUMBERS
#10thClassMathematicsREALNUMBERS
#10thStdMathematics
#SSLCMaths
#FundamentalTheoremofArithmetic
#PrimenumbersandCompositenumbers
#HCFandLCMDefinitionAndExamples
#ProductoftwonumbersequaltoHCF*LCM
#10thGradeMathematicsEnglishMedium
#10thClassMathsExplanationInKannada