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How to Balance ZnS + HBr = ZnBr2 + H2S (and Type of Reaction)
To balance the chemical equation ZnS + HBr = ZnBr2 + H2S, follow these steps:

Step 1: Write the unbalanced equation
ZnS + HBr = ZnBr2 + H2S

On the left side, we have zinc sulfide (ZnS) and hydrogen bromide (HBr).
On the right side, we have zinc bromide (ZnBr2) and hydrogen sulfide (H2S).

Step 2: Count the atoms of each element on both sides
Left side:
Zinc (Zn) = 1 (from ZnS)
Sulfur (S) = 1 (from ZnS)
Hydrogen (H) = 1 (from HBr)
Bromine (Br) = 1 (from HBr)

Right side:
Zinc (Zn) = 1 (from ZnBr2)
Sulfur (S) = 1 (from H2S)
Hydrogen (H) = 2 (from H2S)
Bromine (Br) = 2 (from ZnBr2)

Step 3: Balance the elements one at a time
1. *Balance zinc (Zn):*
Zinc is already balanced with 1 zinc atom on each side (1 in ZnS and 1 in ZnBr2).

2. *Balance sulfur (S):*
Sulfur is already balanced with 1 sulfur atom on each side (1 in ZnS and 1 in H2S).

3. *Balance hydrogen (H):*
On the left side, there is 1 hydrogen atom (from HBr).
On the right side, there are 2 hydrogen atoms (from H2S).
To balance hydrogen, put a coefficient of 2 in front of HBr on the left side.

The equation becomes:
ZnS + 2HBr = ZnBr2 + H2S

4. *Balance bromine (Br):*
On the left side, there are 2 bromine atoms (from 2HBr).
On the right side, there are 2 bromine atoms (from ZnBr2).
Bromine is now balanced.

Step 4: Double-check the balance
Left side:
Zinc (Zn) = 1 (from ZnS)
Sulfur (S) = 1 (from ZnS)
Hydrogen (H) = 2 (from 2HBr)
Bromine (Br) = 2 (from 2HBr)

Right side:
Zinc (Zn) = 1 (from ZnBr2)
Sulfur (S) = 1 (from H2S)
Hydrogen (H) = 2 (from H2S)
Bromine (Br) = 2 (from ZnBr2)

The equation is balanced!

Final Balanced Equation:
ZnS + 2HBr = ZnBr2 + H2S

Type of Reaction:
This is a *double displacement reaction* (also known as a double replacement or metathesis reaction) where zinc sulfide (ZnS) reacts with hydrogen bromide (HBr) to form zinc bromide (ZnBr2) and hydrogen sulfide (H2S).