30 HARD Challenge - Day 18: Python for Beginners: Leetcode Problem #18: 4Sum

In today's session, we dive into the fascinating problem of finding all unique quadruplets that sum up to a target value. This problem, known as 4Sum, builds upon the concepts of the classic Three Sum problem and requires us to use a two-pointer approach to efficiently search for valid quadruplets.

🔍 Problem Overview:
Given an array of integers nums and a target value, our task is to find all unique quadruplets [nums[a], nums[b], nums[c], nums[d]] such that their sum equals the target value.

🛠️ Solution Approach:
We'll approach this problem by employing a two-pointer technique within nested loops. We'll sort the array first to simplify the search process and avoid duplicate quadruplets. Then, we'll iterate through the array, using two pointers to find the remaining elements that sum up to the target value.

💡 Key Concepts:

Sorting the array for efficient traversal and duplicate avoidance.
Using two nested loops for iteration and two pointers for element selection.
Skipping over duplicate elements to ensure uniqueness in the result.
Join us in today's session as we break down the problem, discuss solution strategies, and implement the solution in Python code.

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Happy coding! 💻✨