Скачать или смотреть Resolving Issues with python mysql.connector Not Executing SQL Code

Discover why your `mysql.connector` code isn't updating the database and learn essential fixes to ensure your SQL queries execute successfully.
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This video is based on the question https://stackoverflow.com/q/76715482/ asked by the user 'Michael S' ( https://stackoverflow.com/u/22203453/ ) and on the answer https://stackoverflow.com/a/76715587/ provided by the user 'hamed danesh' ( https://stackoverflow.com/u/22235622/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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Troubleshooting Python MySQL Connector: Why Your SQL Code Isn't Running

When working with databases in Python using mysql.connector, you may encounter situations where your SQL commands—such as updates, inserts, or deletes—do not execute as expected. This can be particularly frustrating when you have a functional code structure that appears to work when using hard-coded values. In this guide, we will address a common problem and explore an effective solution.

The Problem: SQL Code Not Executing

In the provided code, we observe a function called selectedRow() that is intended to execute several SQL queries based on user interaction with a graphical user interface (GUI). Despite following logical steps to prepare and execute these queries, the database is not updating as expected.

Understanding the Context

Here's a brief outline of what the function attempts to accomplish:

Identify the Active Tab: The function detects which tab is currently active within the GUI.

Select the Current Row: It captures the user-selected row from the Treeview widget.

Execute SQL Statements: Depending on the selected row's content, it attempts to execute SQL commands to modify the database.

The function performs these actions but fails at changing the database—leaving users puzzled.

The Solution: Commit Your Changes

The root of the issue lies in the fact that, for SQL commands that modify data (INSERT, UPDATE, DELETE), it is crucial to commit these changes to the database. In mysql.connector, this is achieved using conn.commit().

Step-by-Step Solution

To fix the issue, follow these simple steps:

Locate the Database Connection and Cursor:
Ensure that conn and cursor variables are correctly initialized, as seen in your function.

Add conn.commit():
After executing your SQL commands, insert conn.commit() to finalize the changes in the database.

Modify Your Code Accordingly:
Update the function as follows:

[[See Video to Reveal this Text or Code Snippet]]

Important Notes

Understanding conn.commit():
This method is essential for ensuring that any changes made through SQL commands are saved in the database. Without calling commit(), the changes will remain in a temporary state and will not reflect in the actual database.

Testing Your Changes:
After making these adjustments, test your function to see if the database updates as intended. Always review your output to confirm successful changes.

Conclusion

Working with databases can sometimes lead to tricky challenges like non-executed SQL commands. However, by understanding the necessity of using conn.commit(), you can effectively manage your database interactions and ensure your commands are executed smoothly.

If you continue to face issues or need further assistance, don't hesitate to seek help from programming communities or forums. Happy coding!