Скачать или смотреть #9 FizzBuzz with 4 Threads Explained | wait() vs Semaphore (Optimal Approach)

In this video, we solve the classic FizzBuzz multithreading problem using 4 threads in Java — where each thread is responsible for printing:

Fizz (multiples of 3)
Buzz (multiples of 5)
FizzBuzz (multiples of 3 and 5)
The number (otherwise)

Timelines:
00:00 - Intro & Agenda
00:18 - Problem Statement
02:32 - 1st Approach
04:05 - 1st Approach Code in IDE
11:43 - Why is this approach not optimal ?
14:18 - Intution of Optimal Approach using Semaphores
18:33 - Coding Optimal Approach in IDE
25:13 - Ending Notes and Next Video Agenda

We explore two approaches:
1. ✅ Using synchronized, wait() and notifyAll() — the traditional approach
2. ⚡ Using Semaphore — the optimized and efficient solution

You’ll learn:
How thread synchronization works in Java
The pitfalls of using wait() without notifyAll()
Why semaphores provide better thread control
How to avoid race conditions and deadlocks

🎓 Perfect for Java developers preparing for multithreading interviews or mastering concurrency concepts.

Github: https://github.com/AndyS12/Multithrea...
LinkedIn:   / anand-singh-sn  
Lecture Notes: https://drive.google.com/file/d/1WBTB...

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#Java #Multithreading #Semaphores #ABCPrinterProblem #JavaInterview #ThreadSynchronization #JavaConcurrency #bitsofcode #bitsofcodeanand