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Скачать или смотреть How to Easily Edit Lists Inside Loops and Update Rows Based on Python Conditions

  • vlogize
  • 2025-10-10
  • 0
How to Easily Edit Lists Inside Loops and Update Rows Based on Python Conditions
How to edit list inside loop and update rows based on Python conditionpythonpandasdataframefor loop
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Описание к видео How to Easily Edit Lists Inside Loops and Update Rows Based on Python Conditions

Explore how to edit lists within loops in Python, particularly using Pandas to update DataFrame rows based on specific conditions without traditional looping.
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This video is based on the question https://stackoverflow.com/q/68366350/ asked by the user 'Angel' ( https://stackoverflow.com/u/7484263/ ) and on the answer https://stackoverflow.com/a/68375961/ provided by the user 'Rob Raymond' ( https://stackoverflow.com/u/9441404/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: How to edit list inside loop and update rows based on Python condition

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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How to Easily Edit Lists Inside Loops and Update Rows Based on Python Conditions

Are you working with Pandas in Python and struggling to edit lists inside loops to update DataFrame rows based on specific conditions? If you have a DataFrame and want to identify rows based on a certain criteria—like finding values greater than or equal to 10 and where two columns aren't the same—this post is for you!

The Problem at Hand

Let’s consider the example of a DataFrame:

[[See Video to Reveal this Text or Code Snippet]]

In this DataFrame, you want to replace values in Col1 with values from Col2 for those rows where:

Col3 has a value greater than or equal to 10.

Col1 and Col2 values are not the same.

The desired outcome after applying the conditions should look like this:

[[See Video to Reveal this Text or Code Snippet]]

The Solution

Instead of using traditional loops (which can be inefficient and is generally considered an anti-pattern in Pandas), you can use a masking technique. This approach not only simplifies your code, but it also enhances performance when working with large datasets.

Step-by-Step Breakdown:

Create Your DataFrame: Start by loading your data into a Pandas DataFrame. For demonstration, we'll create it from a multi-line string.

[[See Video to Reveal this Text or Code Snippet]]

Define the Condition: Next, you'll create a condition (mask) that identifies the rows meeting your criteria:

[[See Video to Reveal this Text or Code Snippet]]

Here df["Col3"].ge(10) checks for values in Col3 that are greater than or equal to 10, while (df["Col1"] != df["Col2"]) compares the two columns.

Assign New Values: Finally, update the DataFrame by assigning the values from Col2 to Col1 wherever the condition is met:

[[See Video to Reveal this Text or Code Snippet]]

Final Output

Once you run the above code, you will achieve the desired DataFrame where the applicable changes have been made.

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

Using conditions instead of loops to manipulate DataFrames is a powerful feature of Pandas. It makes your code cleaner and more efficient, especially with large datasets. So next time you find yourself needing to loop through rows in a Pandas DataFrame, consider leveraging masks and vectorized operations instead.

By implementing these strategies, you will streamline your data handling and improve performance in any project involving data transformations.

If you have any questions or need further clarification, feel free to reach out!

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