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Скачать или смотреть How to Easily Extract Property Names from JSON Objects in C#

  • vlogize
  • 2025-03-29
  • 8
How to Easily Extract Property Names from JSON Objects in C#
How to get the names of all properties (without their values) in a json object?c#jsonjson.net
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Описание к видео How to Easily Extract Property Names from JSON Objects in C#

Discover a simple method to get the names of properties in a JSON object using C- with Newtonsoft.Json. Perfect for beginners!
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This video is based on the question https://stackoverflow.com/q/73799804/ asked by the user 'Coconut' ( https://stackoverflow.com/u/16104520/ ) and on the answer https://stackoverflow.com/a/73799900/ provided by the user 'Enigmativity' ( https://stackoverflow.com/u/259769/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: How to get the names of all properties (without their values) in a json object?

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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How to Easily Extract Property Names from JSON Objects in C-

When working with JSON data, developers often encounter the need to analyze and manipulate objects. A common requirement is to extract just the property names from a JSON object without delving into their values. If you’ve found yourself scratching your head over how to achieve this, you’re in the right place! In this guide, we will guide you through a straightforward solution using C- and the popular Newtonsoft.Json library.

The Problem

Let’s consider a scenario where you have the following JSON object as a string:

[[See Video to Reveal this Text or Code Snippet]]

Your goal is to loop through this object and gather the names of the properties: aaaa, bbbb, and ccc. Importantly, you only want the names, not the associated values.

The Solution

Extracting property names from a JSON object in C- is quite simple with the right tools. Here’s how to do it step by step using the Newtonsoft.Json library.

Step 1: Parse the JSON String

First, ensure you have the Newtonsoft.Json package installed in your project. If you haven’t done so, you can add it via NuGet Package Manager with the following command:

[[See Video to Reveal this Text or Code Snippet]]

Now that you have the package, you can begin by parsing the JSON string into a JObject. Here’s how you do this:

[[See Video to Reveal this Text or Code Snippet]]

Step 2: Extract Property Names

Once you have the JSON object parsed, the next step is to extract the property names. You can do this easily using LINQ as shown in the code below:

[[See Video to Reveal this Text or Code Snippet]]

Step 3: Output the Results

Now that you have extracted property names into the names array, you can simply output or utilize them as needed:

[[See Video to Reveal this Text or Code Snippet]]

Example Results

When you run the above code, you will get the following output:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

In just a few lines of code, you can efficiently extract property names from a JSON object in C-. This method is not only simple but also powerful, allowing you to handle any JSON structure you encounter in your applications. Whether you're a seasoned developer or just getting started with JSON and C-, this technique will surely come in handy!

If you want to explore more about JSON manipulation or have other related questions, feel free to reach out or leave a comment below.

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