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Скачать или смотреть Understanding C Macros: Why Your Code Returns -8 Instead of -4

  • vlogize
  • 2025-10-11
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Understanding C Macros: Why Your Code Returns -8 Instead of -4
why is it returning -8 instead of -4..?
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Описание к видео Understanding C Macros: Why Your Code Returns -8 Instead of -4

Learn about C macros and their precedence rules to understand why your code is returning an unexpected value. Find solutions to fix your code for accurate results.
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This video is based on the question https://stackoverflow.com/q/68599443/ asked by the user 'AYUSH Mondal' ( https://stackoverflow.com/u/14577204/ ) and on the answer https://stackoverflow.com/a/68599480/ provided by the user 'ruakh' ( https://stackoverflow.com/u/978917/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: why is it returning -8 instead of -4..?

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Why Is It Returning -8 Instead Of -4? A Dive Into C Macros

When programming in C, encountering unexpected results can often lead to confusion and frustration. A common source of this bewilderment stems from the use of macros and the language's operator precedence. In this post, we'll dissect a coding example to understand why your function is returning -8 instead of the mathematically expected -4. By breaking down the issue and providing solutions, we aim to empower you with the knowledge to avoid similar pitfalls in the future.

The Problem

Suppose you have the following code snippet:

[[See Video to Reveal this Text or Code Snippet]]

When you run this code, you get the output -8, leading you to question why it doesn't return -4 as expected. Understanding the workings of the macro foo is key to resolving this mystery.

Understanding the Macro Expansion

The macro foo(x,y) is defined as x/y + x. Let’s analyze the following line from your code:

[[See Video to Reveal this Text or Code Snippet]]

When this macro is expanded, it translates into:

[[See Video to Reveal this Text or Code Snippet]]

Operator Precedence

In C, operators have a defined precedence which determines the order in which parts of an expression are evaluated. The division operator / has a higher precedence than the addition operator + . Therefore, your expression is interpreted as:

[[See Video to Reveal this Text or Code Snippet]]

Breaking Down the Calculation

Calculate j / 3: Given that j is 3, the calculation yields 1 (because integer division truncates any decimal).

Substituting Back: Now the expression becomes:

[[See Video to Reveal this Text or Code Snippet]]

Final Calculation:

First: -6 + 1 = -5

Then: -5 - 6 = -11

Finally: -11 + 3 = -8

Thus, the output of your code is -8, not -4. This outcome is due to C's operator precedence rules rather than a mathematical mistake.

Solutions to the Problem

To fix this issue, you have a couple of options:

1. Use a Proper Function Instead of a Macro

A more reliable approach is to define foo as a function instead. This eliminates confusion stemming from macro expansion:

[[See Video to Reveal this Text or Code Snippet]]

By using a function, the expression will be evaluated correctly, and you will achieve the desired outcome of -4.

2. Parentheses for Clarity

If you wish to continue using a macro, you can adjust it for clarity by adding appropriate parentheses:

[[See Video to Reveal this Text or Code Snippet]]

This ensures that x is evaluated together as intended.

Caution: However, keep in mind that if the expression for x contains side effects (like incrementing a variable), the macro will evaluate it multiple times, potentially leading to unexpected results or undefined behavior.

Conclusion

Understanding the intricacies of C macros and operator precedence is essential in writing accurate and effective code. By recognizing how macros expand and strategically using functions, you can sidestep the issues of improper evaluation and unexpected outputs.

With this knowledge in hand, you're better equipped to tackle similar scenarios in your programming endeavors. Happy coding!

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