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Скачать или смотреть How to Extract the Signature Type from a Function Pointer in C+ +

  • vlogize
  • 2025-04-09
  • 6
How to Extract the Signature Type from a Function Pointer in C+ +
How to get the the signature type from the function pointer type?c++c++17
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Описание к видео How to Extract the Signature Type from a Function Pointer in C+ +

Learn how to get the signature type from a function pointer type in C+ + with step-by-step guidance and code examples.
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This video is based on the question https://stackoverflow.com/q/75183757/ asked by the user 'asmbaty' ( https://stackoverflow.com/u/4910232/ ) and on the answer https://stackoverflow.com/a/75183790/ provided by the user 'HolyBlackCat' ( https://stackoverflow.com/u/2752075/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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How to Extract the Signature Type from a Function Pointer in C+ +

When working with function pointers in C+ + , there are times when you'll want to extract the signature type from a function pointer in order to use it with std::function. This can be especially useful if you want to store a function pointer in a more flexible way or pass it around in your application. In this post, we'll explore how to achieve this by breaking it down in a simple, easy-to-understand manner.

The Problem

Let’s say you have defined a function pointer type like this:

[[See Video to Reveal this Text or Code Snippet]]

You want to create a std::function object using the signature of FType. A common question might be: “How can I extract the signature type from this function pointer type?”

Understanding Function Pointer and std::function

Function pointers are used in C/C+ + to point to functions. However, std::function is a standard library template that can be used to encapsulate function pointers, among other callable entities. It provides a way to define a type-safe way to store and invoke functions.

To create a std::function object from a function pointer type, we need to understand how to remove the pointer part (*) to get the actual signature of the function. This can be done using templates, specifically std::remove_pointer_t in C+ + 17.

Step-by-Step Solution

Here’s how you can carry out this operation step by step:

Define the Function Pointer Type: Start by defining your function pointer type, as done earlier.

[[See Video to Reveal this Text or Code Snippet]]

Using std::remove_pointer_t: By applying std::remove_pointer_t, you can extract the actual function signature from the pointer type.

[[See Video to Reveal this Text or Code Snippet]]

Creating the std::function Object: Combine the above method to construct your std::function object.

Here’s how the complete code would look:

[[See Video to Reveal this Text or Code Snippet]]

Additional Insights

C+ + 17 Requirement: Note that std::remove_pointer_t is available in C+ + 17 and later, so make sure your development environment supports at least this version of C+ + .

Flexibility of std::function: Using std::function gives you the advantage of flexibility since it can store any callable type that matches the signature, not just function pointers. This means you could also store lambdas or other callable objects that have a compatible signature.

Conclusion

Extracting the signature type from a function pointer in C+ + can initially seem daunting, but with the use of std::remove_pointer_t and std::function, it is quite straightforward. You just need to remember the steps and apply them carefully in your code. This straightforward approach greatly increases the usability of function types in modern C+ + programming.

Now that you know how to do this, make sure to try it in your own C+ + projects to enhance your function handling capabilities!

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