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How to find the percent composition of NH4I (Ammonium Iodide)
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*Finding the Percent Composition of NH₄I (Ammonium Iodide):*

1. Identify the elements in NH₄I:
Nitrogen (N)
Hydrogen (H)
Iodine (I)

2. Find the atomic masses (from the periodic table):
Nitrogen (N): 14.01 g/mol
Hydrogen (H): 1.008 g/mol
Iodine (I): 126.90 g/mol

3. Determine the molar mass of NH₄I:
NH₄I = (14.01 × 1) + (1.008 × 4) + 126.90
NH₄I = 14.01 + 4.032 + 126.90 = 144.942 g/mol

4. Calculate the percent composition for each element:
Percent of N: (14.01 / 144.942) × 100 = 9.67%
Percent of H: (4.032 / 144.942) × 100 = 2.78%
Percent of I: (126.90 / 144.942) × 100 = 87.55%

*Percent Composition of NH₄I:*
Nitrogen (N): 9.67%
Hydrogen (H): 2.78%
Iodine (I): 87.55%
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