JEE Advanced 2022 || Coordination Compound ||

Content in this Video Lecture-

LIST-I contains metal species and LIST-II contains their properties
List -I
[Cr(CN)6]4-
(P) t2g orbitals contain 4 electrons
(II) [RuCl6]2-
(Q) μ (spin - only) = 4.9 BM
(III) [Cr(H2O6)]2+
(R) Low spin complex ion
(IV) [Fe(H2O)6]2+
(S) Metal ion in 4+ oxidation state
(T) d4 species
[Given: Atomic number of Cr = 24, Ru = 44, Fe = 26]
Match each metal species in LIST-I with their properties in LIST-II, and choose the correct option
(A) I→ R, T; II → P, S; III → Q, T; IV → P, Q
(B) I→ R, S; II → P, T; III → P, Q; IV → Q, T
(C) I→ P, R; II → R, S; III → R, T; IV → P, T
(D) I → Q, T; II → S, T; III → P, T; IV → Q, R


Our video is useful for Up /CBSE/ICSE Board students as well as students who are preparing for IIT JEE/ KVPY and other useful exams. On this YouTube channel we will give you better content which will help you in your board exams as well as other competitions. So, Please Like, Share and Subscribe to "Aastha Chemistry Classes" YouTube channel and click the bell icon to get new video updates.
Thank You


#jeesolution
#jeeadvanced
#coordinationcompound
#jeeadvance2022
#iitjeemainschemistry
#cbse12chemistry
#aasthachemistryclasses
#iitjeeadvancechemistry
#iitjeeadvancechemistry
#aasthachemistryclasses
#iitjeemainschemistry