Discover how to effectively use Java streams to find males that are present in one list but not in another with this step-by-step guide.
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This video is based on the question https://stackoverflow.com/q/74981967/ asked by the user 'TheStranger' ( https://stackoverflow.com/u/9545125/ ) and on the answer https://stackoverflow.com/a/74982245/ provided by the user 'lukwas' ( https://stackoverflow.com/u/12141701/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.
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Streaming the Difference Between Two Lists of Males in Java
In the world of Java programming, working with lists is a common task. You may face scenarios where you need to compare two lists based on specific criteria, such as gender. One interesting challenge is to create a new list of male persons who are present in one list but absent in the other. In this guide, we will explore how to efficiently achieve this using Java streams.
The Problem Statement
Suppose you have a Person class defined like this:
[[See Video to Reveal this Text or Code Snippet]]
You also have two lists of persons:
List A:
Mike, male
Jane, female
Ellen, female
Ben, male
Jimmy, male
Maria, female
List B:
Ben, male
Maria, female
Jane, female
Brian, male
Sofia, female
John, male
Jimmy, male
Your goal is to create a new list containing names of all males who are not present in both lists. Therefore, the expected output should be:
Expected Output:
Mike, male
John, male
Brian, male
The challenge? The filtering should work both ways: we need to include males from List A that aren't in List B and vice versa.
The Solution
Using Java streams, we can achieve this elegantly. Let’s break down the solution into clear steps for better comprehension.
Basic Solution Using Streams
The simplest approach leverages the Stream.concat() method to combine the two filtered streams into one result. Here's how you can do it:
[[See Video to Reveal this Text or Code Snippet]]
Step-by-Step Breakdown
Creating Streams: Convert both lists into streams using a.stream() and b.stream().
Filtering Criteria:
For list A, filter for males who are not in list B.
For list B, filter for males who are not in list A.
Combining Streams: Use Stream.concat() to merge the results of both filtered streams.
Collecting Results: Gather the final results into a new list using collect(Collectors.toList()).
Improved Readability with Intermediate Results
If you prefer more readable code or need to store the intermediate results, you can break the solution into smaller parts like so:
[[See Video to Reveal this Text or Code Snippet]]
Benefits of This Approach
Readability: Storing partial results makes the code easier to understand.
Reusability: You can reuse aNotB and bNotA lists elsewhere in your code if needed.
Clear Logic Flow: Each step is logical and clear, making debugging simpler.
Conclusion
In this post, we tackled an interesting problem: finding males that exist in one list but not in another using Java streams. Whether you prefer the concise method or a more detailed approach, with the tools provided by Java's Stream API, you can accomplish list comparisons efficiently. Now you can apply this methodology in your own Java projects and enhance your programming skills!
By knowing how to filter lists, you have a powerful weapon in your coding arsenal that will help you tackle many similar challenges in your future endeavors. Happy coding!
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