In this project, I used a homemade toroidal coil wound with 28 gauge enameled copper wire.
The coil has 11 turns – 0 – 11 turns (a center-tapped design), perfect for a boost circuit like a Joule Thief.
For switching, I used a CL100 NPN transistor, which handles higher current than small signal transistors.
On the base, I used a 100Ω resistor to limit current and control the transistor's switching.
The power supply is a 3V battery (2×1.5V cells), and the output drives 4 white LEDs in parallel — each one rated around 3V.
Even with this simple setup, all 4 LEDs glow brightly using just a 3V input, thanks to the voltage-boosting coil and efficient switching of the CL100 transistor.
🛠️ This kind of circuit is great for torches or emergency lights where you want to run multiple LEDs from a low-voltage battery."
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✅ Optional On-Screen Caption Ideas:
"Coil: 28 SWG Copper Wire, 11-0-11 Turns"
"Transistor: CL100 NPN"
"Base Resistor: 100Ω"
"LEDs: 4× 3V White LEDs in Parallel"
"Power: 3V (2 AA Batteries)"
I built a simple Joule Thief circuit to test battery performance. I used the exact same setup on both sides — same white LED, same coil, same transistor — but with different batteries: Duracell on one side, and Eveready on the other.
After running both setups continuously for 3 days, I noticed something interesting —
👉 The LED powered by Duracell was still glowing bright,
👉 While the one using Eveready had dimmed by around 30%.
This clearly shows that Duracell batteries are more efficient.
Why?
✅ Duracell has higher capacity (up to 2500mAh)
✅ Lower internal resistance, so there's less voltage drop under load
✅ And they’re better suited for high-drain circuits like the Joule Thief
On the other hand, cheaper Eveready batteries lose voltage faster, which reduces the LED brightness over time.
🎯 So if you're building a long-lasting, high-brightness torch or DIY project, I recommend using quality batteries like Duracell.
Cheaper batteries might work at first, but their performance drops quickly.
If you found this test useful, don’t forget to like, share, and subscribe!"
Turn 1.5V Into 3V – Light Up an LED Without Any IC!
In this amazing DIY electronics short, I’ll show you how to light a 3V LED using only a 1.5V battery by building a manual voltage doubler circuit. No transformer, no special IC—just two capacitors and a simple DPDT (Double Pole Double Throw) slide switch.
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⚙️ What You’ll See in This Video:
✅ Step-by-step connection of the components
✅ How to charge capacitors in parallel
✅ How flipping the switch connects them in series to double the voltage
✅ LED glowing brightly with just one battery—thanks to basic capacitor magic!
🎯 Components Used:
1.5V AA Battery
2 Electrolytic Capacitors (e.g., 470µF or 1000µF)
DPDT Slide Switch
3V LED
100 Ohm Resistor
Connecting wires
💡 How It Works:
1. In the first position, the switch connects both capacitors in parallel to charge them with 1.5V.
2. In the second position, the switch changes the connection so that the two capacitors are now in series. This adds their voltages together to produce around 3V.
3. The LED lights up briefly as this doubled voltage flows through the resistor and the LED.
⚠️ This is a manual process, so the LED glows only when you toggle the switch and the capacitors still hold charge.
In this short video, I’ll show you how to increase voltage using a simple trick — just a capacitor, two diodes, and a push button! This is a basic charge pump or voltage booster circuit that lights up an LED with a smart manual technique.
🔧 What’s Inside:
How the circuit works
How pressing a button shifts voltage
⚡ No transformer, no IC — just pure electronics magic!
📌 Components Used:
1x Electrolytic Capacitor
2x Diodes (1N4007 or similar)
1x Push Button
1x LED
1x Resistor
Jumper wires & Breadboard
💡 Try it yourself and share your results in the comments!
📺 Don’t forget to Like, Comment, and Subscribe for more cool electronics hacks and DIY circuits!
#VoltageBooster #ElectronicsDIY #ChargePump #LEDTrick #BreadboardProject #TransistorJugaad #ElectronicsForBeginners
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