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Скачать или смотреть Understanding Why View within Switch-Case is Not Working in React Native Functional Components

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  • 2025-04-04
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Understanding Why View within Switch-Case is Not Working in React Native Functional Components
Why View within Switch-Case not working with functional component in react-nativereactjsreact native
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Описание к видео Understanding Why View within Switch-Case is Not Working in React Native Functional Components

Discover the reasons behind the issue of using `Switch-Case` in React Native functional components, along with a structured solution to successfully render different views based on conditions.
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This video is based on the question https://stackoverflow.com/q/69187918/ asked by the user 'user2648519' ( https://stackoverflow.com/u/2648519/ ) and on the answer https://stackoverflow.com/a/69187995/ provided by the user 'Drew Reese' ( https://stackoverflow.com/u/8690857/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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Understanding Why View within Switch-Case is Not Working in React Native Functional Components

In the world of React Native development, you might encounter a situation where you are trying to render different components based on a certain condition using a switch-case statement. However, you could face issues when you notice that your component is not rendering as expected. This short guide will help you identify the problem and provide a straightforward solution.

The Problem

Consider the following situation in a React Native application: you're building a functional component named LoadingView, and you're attempting to display different loading states based on the value of viewKey.

Your code looks something like this:

[[See Video to Reveal this Text or Code Snippet]]

Why Isn’t It Working?

When you attempt to run the above code, you find that it fails to render as expected. The primary reason for this issue is that a function you defined for rendering—SwitchCase—is not being called correctly. Instead, you are merely referencing it.

The Solution

To rectify this situation, you need to ensure that:

**You invoke the SwitchCase function when returning from your main component.

Return valid JSX from within each conditional case of your SwitchCase function.

Here’s How to Fix It

Modify the SwitchCase function to ensure it returns the JSX, and then call the function to provide the rendered output. Here is the adjusted code:

[[See Video to Reveal this Text or Code Snippet]]

Breakdown of Adjustments

Return the JSX: Each case within the SwitchCase function should return the corresponding JSX enclosed in parentheses.

Function Invocation: Instead of just returning the function reference, invoke it by writing SwitchCase() in the return statement of your main component.

Conclusion

By following these steps, you can efficiently tackle the issue of rendering components conditionally within a switch-case structure in React Native functional components. Remember to always return valid JSX from your component functions and ensure you are invoking them properly. This way, your application will behave as intended without rendering issues.

With this knowledge at your fingertips, you are well on your way to mastering React Native development!

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