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We determine the values of
𝛼
α and
𝛽
β step by step using:
✅ Taylor series expansion of sinx and sin(βx)
✅ Order matching to find α=1
✅ Limit simplification to get 𝛽 = 1/6



✅ Final answer 6(α+β)=7

This question is perfect for JEE Advanced and JEE Mains aspirants as it strengthens concepts of limits, L’Hospital’s rule alternatives, and series expansions.

📌 What you’ll learn:

How to apply series expansion in limits

How to eliminate terms to get a finite limit

A neat step-by-step way to handle tricky limits

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jee advanced maths, jee limits problems, taylor series jee, series expansion jee advanced, jee mains maths, tricky limits jee, limits by series expansion, algebra of limits jee, l hospital rule alternative, jee maths important problems, dagur maths

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