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Скачать или смотреть application of mole!! numericals based concept of mole!! class 11!! chapter 1!! lecture 19

  • vedansh chemistry
  • 2023-08-25
  • 49
application of mole!! numericals based concept of mole!! class 11!! chapter 1!! lecture 19
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The concept of "mole" in the context of IIT-JEE and NEET refers to Avogadro's constant, which is approximately 6.022 × 10²³. It represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance. This concept helps in connecting the macroscopic world of grams and kilograms to the microscopic world of atoms and molecules, enabling us to perform calculations involving the amount of substances in chemical reactions. Is there something specific you'd like to know about the mole concept.The concept of "mole" in the context of IIT-JEE and NEET refers to Avogadro's constant, which is approximately 6.022 × 10²³. It represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance. This concept helps in connecting the macroscopic world of grams and kilograms to the microscopic world of atoms and molecules, enabling us to perform calculations involving the amount of substances in chemical reactions. Is there something specific you'd like to know about the mole concept

Sure, I can help with that! The mole concept is often used in numerical problems to relate the amount of a substance to its mass, number of particles, or volume. Here's a basic outline of how it works:

Molar Mass: The molar mass of a substance is the mass of one mole of that substance. It's expressed in grams per mole (g/mol). To calculate the mass of a given number of moles, you use the formula: Mass (g) = Molar Mass (g/mol) × Moles.

Number of Particles: The number of particles in a substance is given by Avogadro's constant (6.022 × 10²³) per mole. To calculate the number of particles, you use the formula: Number of Particles = Moles × Avogadro's Constant.

Volume of Gas: For gases, one mole of an ideal gas occupies a volume of 22.7 liters at standard temperature and pressure (STP). You can use this relationship to calculate volume: Volume (liters) = Moles × 22.7 (at STP).

When solving problems, make sure to convert units as needed to ensure they are consistent with the given data. Also, be aware of any additional information provided in the problem, such as chemical reactions or physical conditions.

If you have a specific numerical problem in mind or need more detailed explanations, feel free to provide it!

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