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Скачать или смотреть Understanding Swift Closures and Capture Lists: Why Foo is nil?

  • vlogize
  • 2025-03-17
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Understanding Swift Closures and Capture Lists: Why Foo is nil?
Can somebody please explain this behaviour?swift
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Описание к видео Understanding Swift Closures and Capture Lists: Why Foo is nil?

Dive into the world of Swift closures and learn why weak references might lead to unexpected behavior such as a `nil` value in your captured variables.
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This video is based on the question https://stackoverflow.com/q/75950654/ asked by the user 'user1670679' ( https://stackoverflow.com/u/1670679/ ) and on the answer https://stackoverflow.com/a/75950847/ provided by the user 'vadian' ( https://stackoverflow.com/u/5044042/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Can somebody please explain this behaviour?

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Understanding Swift Closures and Capture Lists: Why Foo is nil?

When working with Swift, the way closures capture variables can be both a powerful feature and a source of confusion. A common question that arises among developers is why certain values appear as nil when they are expected to hold a valid reference. This post seeks to clarify this concept by dissecting a specific example involving a class and a closure.

The Problem

Let's consider a simple class structure to illustrate the issue:

[[See Video to Reveal this Text or Code Snippet]]

We then create an instance of MyClass like so:

[[See Video to Reveal this Text or Code Snippet]]

Expected Behavior

At this point, one might expect the output to be Foo: Optional(1). However, upon running this code, the actual output is Foo: nil. This outcome can be perplexing, especially if you're confident that foo hasn't been deallocated.

The Explanation

To understand why this happens, we need to delve deeper into how closures work in Swift, particularly focusing on what's known as the Capture List.

What is a Capture List?

In Swift, a closure can capture and store references to values or variables from its surrounding context. The syntax [weak foo] in the closure is a way to specify that we want a weak reference to foo:

Weak Reference: This means that foo does not increase the reference count of the object it references. If the referenced object is deallocated, the variable will automatically be set to nil.

Why foo is nil

When we include foo in the capture list as [weak foo], we're saying:

"Capture a weak reference to foo."

At the time the closure is created, foo is not yet fully initialized/valid because it is still in a state of initialization. Thus, the closure receives a nil value for foo.

This is why, when we call foo?.fnc(), the value of foo inside the closure is indeed nil, resulting in:

[[See Video to Reveal this Text or Code Snippet]]

What Happens Without Weak Reference

If we do not specify foo as weak:

[[See Video to Reveal this Text or Code Snippet]]

Now, foo is captured strongly, meaning the closure retains a strong reference to it, allowing for access to foo.int. This results in:

[[See Video to Reveal this Text or Code Snippet]]

Key Takeaways

Closure Capture: Understand whether you need a weak or strong reference in your closures.

Initialization Context: Be aware of the initialization state of variables being captured by closures.

Memory Management: Use weak references judiciously to avoid retain cycles while still ensuring that you have the access you expect.

Conclusion

Navigating the behavior of closures in Swift can be challenging, especially when it comes to how variables are captured. This example illustrates how a weak reference can lead to unexpected outcomes. By leveraging the concepts of strong and weak references, developers can write cleaner and more effective Swift code.

If you have more questions or comments about Swift closures, feel free to share below!

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