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Oxidation Number of Cr in CrO5? | Butterfly Structure Exception | OSSTET Q65 #shorts #osstet #short
OSSTET Chemistry Question 65 Solution | Oxidation Number of Cr in CrO5

Description: In this video, we provide the detailed solution for Question No 65 from the OSSTET Chemistry (PCM) Previous Year Question Paper. This question tests your understanding of Structure-based Oxidation Numbers.

📝 Question Discussed: "The oxidation number of Cr in CrO
5
​
is:" (A) +10 (B) +6 (C) +4 (D) +3

💡 Concept Explained:

Common Mistake: If we calculate using the normal formula (x+5(−2)=0), we get x=+10. This is WRONG because Chromium cannot lose 10 electrons (it only has 6 valence electrons).

The Structure: CrO
5
​
has a Butterfly Structure.

It has 4 Peroxide Oxygens (O-O linkage) with oxidation state -1.

It has 1 Oxide Oxygen (double bonded) with oxidation state -2.

Correct Calculation:

x+4(−1)+1(−2)=0
x−4−2=0
x=+6
Answer: Option (B) +6.

Watch the video to master these Chemistry Exceptions!

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