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Скачать или смотреть Understanding super in Java Generics: Why It Doesn't Work with User-Defined Classes

  • vlogize
  • 2025-04-09
  • 9
Understanding super in Java Generics: Why It Doesn't Work with User-Defined Classes
super in Generics T super User defined class not workingjavagenerics
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Описание к видео Understanding super in Java Generics: Why It Doesn't Work with User-Defined Classes

Explore the intricacies of using `super` in Java Generics, including why it is not effective with user-defined classes and the correct approach to utilizing it.
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This video is based on the question https://stackoverflow.com/q/76028395/ asked by the user 'CuriousMind' ( https://stackoverflow.com/u/3438473/ ) and on the answer https://stackoverflow.com/a/76028529/ provided by the user 'Sweeper' ( https://stackoverflow.com/u/5133585/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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Understanding super in Java Generics: Why It Doesn't Work with User-Defined Classes

Java Generics can be a challenging concept to grasp, especially when it comes to understanding how the keywords super and extends function within the framework. Let's dive into the common misconceptions and clarify the purpose and limitations of these keywords, particularly when applied to user-defined classes.

The Problem: Confusion Over super in Generics

When writing generics in Java, you may come across methods that use extends and super. For example, in the class code provided, a method is attempting to use super as follows:

[[See Video to Reveal this Text or Code Snippet]]

However, this does not produce the desired outcomes, leading many to wonder why this syntax is invalid and how to express it correctly.

The Solution: Understanding the super Keyword

Why T super Animal is Not Valid

Lack of Utility: Using T super Animal does not provide enough information about the type T. Since T could be any supertype of Animal, you lose the ability to call animal-specific methods on t, except for methods defined in Object (the root class of Java objects). For instance:

[[See Video to Reveal this Text or Code Snippet]]

The only methods you can safely invoke on t are those inherited from Object. Essentially, this reduces the utility of your method and behaves similarly to:

[[See Video to Reveal this Text or Code Snippet]]

Return Type Limitations: If you attempt to use the super bound in the return type, you still face similar constraints:

[[See Video to Reveal this Text or Code Snippet]]

This does not help much, as you'd know you could return an instance of Animal or any of its subclasses but still miss the specificity required for meaningful operations.

When Is super Useful?

While T super Animal does not work for parameterized types, you can use super effectively with wildcards. For example:

[[See Video to Reveal this Text or Code Snippet]]

In this scenario, the method allows the caller to pass any list that can accept an instance of Animal or its subclasses, such as List<Object> or List<LivingThing>. This versatility is where super shines.

Conclusion: Stick to extends for Generics

When working with generics in Java, remember:

Use extends for upper bounds to gain access to all methods of the specified class and its subclasses.

Use super in wildcards to allow broader types while maintaining functionality, particularly for adding items to a collection.

Final Thoughts

Understanding how super and extends work in the context of Java Generics is crucial for effective programming. By recognizing the limitations of the super keyword with user-defined classes, you can make better design choices in your code, leading to more robust and maintainable applications.

Feel free to ask any further questions about Java Generics or share your experiences below!

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