📄All the notes & code are uploaded : https://leetcode.com/problems/meeting...
❓Question Link : https://leetcode.com/problems/meeting...
🧠 Question Description
You are given `n` meeting rooms and a list of `meetings`, where each meeting has a start and end time. A meeting must be assigned to exactly one room. If multiple rooms are available, assign the meeting to the lowest-indexed available room. If no room is available, delay the meeting to the earliest possible start time based on when rooms free up. Each room can host only one meeting at a time, and meetings cannot be interrupted. The goal is to return the *room number* that hosts the **maximum number of meetings**. In case of a tie, return the smallest room number. This problem tests greedy resource allocation, min-heap scheduling, and fair scheduling principles. It’s a powerful example of how to use heaps (priority queues) for managing real-time resources and handling overlaps, delays, and capacity constraints efficiently.
🏷️Tags / Concepts Covered
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📌 Timestamps :
00:00 General Discussion
00:54 Question Explanation
6:52 Observation
9:46 Dry Run to Derive Conditions + Edge Case
20:14 Code
24:33 Set Method Code
25:27 End Discussion
💬 🔔 Updates / Notices
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