Скачать или смотреть Leetcode | 2551. Put Marbles in Bags | Solution

📝 Code Description:
This code solves a problem where marbles with given weights must be divided into k groups, and the goal is to find the difference between the maximum and minimum possible scores. The score of a grouping depends on the first and last marble in each group. To achieve this efficiently, the code first calculates the sum of every pair of adjacent weights, since these sums determine where groups can be split. After storing these pair sums in an array, it sorts the array to easily access the smallest and largest values. The minimum score is formed by adding the smallest k−1 pair sums, while the maximum score is formed by adding the largest k−1 pair sums. By subtracting these two totals, the code returns the largest possible difference between the maximum and minimum scores achievable through optimal partitioning.

🔖 Tags:
Greedy Algorithm
Sorting
Array Manipulation
Pair Sum Logic
Partitioning Problem
DSA
Java Coding
Competitive Programming
LeetCode Problem
Algorithm Optimization

🔍 Keywords:
Put Marbles in Bags
Greedy Approach
Pair Sum Array
Max–Min Difference
Sorting Algorithm
Boundary Selection
Java DSA Solution
Optimal Partitioning
Array Operations
Efficient Algorithm

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