Discover the secrets to using Python 3 list comprehensions effectively, ensuring your code filters words starting with vowels without returning empty lists.
---
This video is based on the question https://stackoverflow.com/q/62732163/ asked by the user 'Abhigyan' ( https://stackoverflow.com/u/7084289/ ) and on the answer https://stackoverflow.com/a/62732283/ provided by the user 'zack256' ( https://stackoverflow.com/u/6806782/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.
Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Python 3 : empty list returned instead of list of words starting with vowel using comprehension
Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.
If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
---
Mastering Python 3 List Comprehensions: How to Filter Words Starting with Vowels
As you dive into the world of Python programming, one of the many concepts you'll come across is list comprehensions. These are a powerful feature that allows you to create lists in a more concise and readable way. However, transitioning from traditional looping to list comprehensions can sometimes be tricky, especially when you're just starting out. If you've found yourself grappling with an issue where your list comprehension returns an empty list instead of a desired output, you're not alone.
The Problem
Imagine you have a list of strings, and you want to filter this list to obtain only the words that start with a vowel. The traditional looping approach works as intended, but when you try to implement the same functionality using list comprehensions in Python 3, you encounter an empty list as the output. This can be perplexing, especially when your input appears to contain valid data.
Here’s an example of a working looping code:
[[See Video to Reveal this Text or Code Snippet]]
When you attempt to convert this logic into a list comprehension, the following code ends up yielding an empty list:
[[See Video to Reveal this Text or Code Snippet]]
Despite having valid input lists like ['a', 'e', 'i', 'o', 'u'], the output is still [].
Understanding the Issue
The crux of the problem lies in how the list_vowel variable is defined in your comprehension. In the faulty code, you have defined list_vowel as follows:
[[See Video to Reveal this Text or Code Snippet]]
This means that the only element in list_vowel is the string "aeiou", which obviously does not contain individual vowel characters like a, e, i, o, or u. Thus, when your code checks if x[0] in list_vowel, it never finds a match, resulting in an empty output list.
The Solution
To fix this issue, you can redefine list_vowel in one of the following ways:
Using a list of individual vowels:
[[See Video to Reveal this Text or Code Snippet]]
Using a string of vowels directly:
[[See Video to Reveal this Text or Code Snippet]]
Both of these options correctly contain the vowels you're looking for, allowing your list comprehension to function as expected.
Example of the Corrected Code
Here’s how your corrected list comprehension should look:
[[See Video to Reveal this Text or Code Snippet]]
Conclusion
Mastering the use of list comprehensions in Python 3 can streamline your code and make it more efficient. However, it's crucial to ensure that your criteria for filtering elements are defined correctly. By carefully constructing your iterable lists and understanding how they interact with your comprehension logic, you can avoid the frustration of ending up with empty outputs.
Now that you have the tools to refine your list comprehension skills, go ahead and try it out in your own projects—it’s a great way to enhance both the readability and efficiency of your code!
Информация по комментариям в разработке