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LeetCode 27 Remove Element | Two Pointer Approach Explained Step-by-Step

In this video, we solve the Remove Element problem using the Two Pointer Technique in JavaScript.
You’ll learn how to overwrite the array in-place, understand how two pointers work together, and get a full explanation of Time and Space Complexity.

🔍 Approach
We use two pointers:
i → iterates through the array
k → tracks the position of the next valid element

Whenever we find an element not equal to val, we move it to the front.
At the end, the first k elements are our result.

💡 Complexity
Time Complexity: O(n) — single pass through the array
Space Complexity: O(1) — in-place modification

var removeElement = function(nums, val) {
let k = 0;
for (let i = 0; i less than nums.length; i++) {
if (nums[i] !== val) {
nums[k] = nums[i];
k++;
}
}
return k;
}

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