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Скачать или смотреть Updating 2D Array in Python: How to Correctly Set Diagonal Elements

  • vlogize
  • 2025-05-25
  • 0
Updating 2D Array in Python: How to Correctly Set Diagonal Elements
Updating 2D array in pythonpythonarraysloopsmultidimensional array
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Описание к видео Updating 2D Array in Python: How to Correctly Set Diagonal Elements

A guide on how to update a 2D array in Python to set only the diagonal elements while avoiding common pitfalls.
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This video is based on the question https://stackoverflow.com/q/72241545/ asked by the user 'Achintya Ranjan Chaudhary' ( https://stackoverflow.com/u/6871676/ ) and on the answer https://stackoverflow.com/a/72241585/ provided by the user 'Sash Sinha' ( https://stackoverflow.com/u/6328256/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Updating 2D array in python

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Understanding Arrays in Python: The 2D Array Problem

Working with arrays in Python can sometimes feel complex, especially when dealing with multidimensional arrays. A common problem that arises is how to update the elements of a 2D array, particularly when you want to modify only the diagonal elements.

The Issue

In our example, we attempted to create a 2D array (or "table") where we wanted to set all the diagonal elements to a specific value, like 9. However, the method employed resulted in all elements being set to 9. Let’s take a closer look at the problematic code:

[[See Video to Reveal this Text or Code Snippet]]

What Happened?

The issue stems from the way the 2D array is initialized. The line table = [[0] * size] * size creates a list that contains references to the same inner list rather than distinct lists. Therefore, modifying one will affect all, which is not what we want in this scenario.

The Solution: Proper Initialization of a 2D Array

To correct this issue, we need to ensure that each row of the array is an independent list. We can achieve this by using a nested list comprehension. Here’s how to do it:

[[See Video to Reveal this Text or Code Snippet]]

Steps Breakdown

Initialize with Nested List Comprehension:

Use [[0 for _ in range(size)] for _ in range(size)] to create a matrix where each row is a unique list.

Set the Diagonal Elements:

Loop through the indices of the rows and columns using for i in range(size): and set table[i][i] = 9.

This ensures only the diagonal elements are assigned the value 9.

Output the Table:

Finally, use a loop to print each row of the table, revealing a nicely formatted matrix with the desired diagonal.

Expected Output

When you run the corrected code, the output will be:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

In conclusion, we successfully addressed the problem of updating a 2D array in Python by ensuring proper initialization of the array to allow selective changes to its elements. This approach not only resolves the issue but also highlights the importance of understanding how Python handles lists and references.

By using distinct lists for each row, we can efficiently manipulate elements as intended. Always remember that small mistakes in initialization can lead to significant issues in data manipulation!

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