Скачать или смотреть QuickField Sample: Ampere's force law

Ampere's force law

This is an example of calculation with QuickField FEA Software.
http://quickfield.com/advanced/ampere...


Ampere force law, magnetic force

This verification example compares the force of attraction between two thin parallel current-currying wires given by Ampere's law and calculated in QuickField using three formulations: magnetostatics, time harmonics and transient magnetics.

Given:
I = 1 A - current of each wire;
f = 50 Hz - frequency in time harmonics and transient magnetics problems;
r = 1 m - distance between the wires.

Task:
Calculate interaction force (per meter of length) between two wires and compare with the value given by the Ampere's force law.

Solution:
Currents are set as linear ones. This way the model completely corresponds to Ampere's formulation.
In the time harmonics problem peak amplitude value of current is set √2·I.
In the transient magnetics current is set via formula I(t) = √2·I · sin(2·180·50·t).

According to the Ampere's law* the force of the interaction between two parallel wires is determined as:
F = 2·(μ0/4π) · I·I / r [N/m]

Results:

Ampere's law:
F = 2·(μ0/4π) · 1·1/ 1 = 2·10-7 [N/m]


*Wikipedia: Ampere's force law.

Download simulation files http://quickfield.com/examples/ampere...