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Part-8 | 11th Units & Measurements | Screw Gauge_Least Count, Positive & Negative Zero Error, Measured & True Value with NEET, CBSE & JEE Questions | Akash Sir Physics

Timeline of Topics👇
00:00 | Introduction

00:45 | Screw Gauge and its least count with pitch

06:24 | Measured value and true value

07:18 | Positive and negative zero error

10:08 | JEE 2021 & NEET_Assertion (A): If in five complete rotations of the circular scale, the distance travelled on main scale of the screw is 5mm and there are 50 total divisions on circular scale, then least count is 0.001cm.
Reason (R): Least Count=Pitch/(Total divisions on circular scale)
In the light of above statements, choose the most appropriate answer from the options given below:

12:27 | JEE 2020 & NEET_Using screw gauge of pitch 0.1cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as:

14:03 | JEE 2022 & NEET_A screw gauge of pitch 0.5mm is used to measure the diameter of uniform wire of length 6.8cm, the main scale reading is 1.5mm and circular scale reading is 7. The calculated curved surface area of wire to appropriate significant figures is: [Screw gauge has 50 divisions on its circular scale]

19:22 | JEE 2023 & NEET_In a screw gauge, there are 100 divisions on the circular scale and the main scale moves by 0.5 mm on a complete rotation of the circular scale. The zero of circular scale lies 6 divisions below the line of graduation, when two studs are brought in contact with each other. When a wire is placed between the studs, 4 linear scale divisions are clearly visible while 46th division of the circular scale coincide with the reference line. The diameter of the wire is_____

24:44 | NEET 2018 & JEE_A student measured the diameter of a steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is:

26:47 | JEE 2016 & NEET_A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the 45th division coincides with the main scale line and zero of the main scale is barely visible. What is the thickness of the sheet if the main scale reading is 0.5 mm and the 25th division coincides with the main scale line?

30:29 | JEE 2021 & NEET_Student A and Student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is 0.322 cm. The absolute value of the difference between the final circular scale readings observed by the students A and B is__.
[Figure shows position of reference ‘O’ when jaws of screw gauge are closed] Given pitch = 0.1cm.

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