Скачать или смотреть Exercise 14.1 class 10 maths solutions | best method to solve probability class 10 | NCERT SOLUTIONS

Exercise 14.1 class 10 maths solutions | best method to solve probability class 10 | NCERT SOLUTIONS
👉 In this video, we will solve Class 10 Maths NCERT Exercise 14.1 (Probability) with step-by-step explanation in simple language.

📘 Topics Covered:

Concept of Probability

Solving Ex 14.1 Questions

Important Questions for Board Exams 2025

Easy tricks to score full marks


This video will help you in Class 10 Board Exam Preparation 2025 and give you complete clarity on Probability Chapter.

📌 Watch the full video to clear all your doubts.
📌 Don’t forget to LIKE 👍, SHARE 🔁 and SUBSCRIBE 🔔 for more Class 10 Maths NCERT solutions.
#Class10Maths #NCERTSolutions #ProbabilityClass10 #Exercise14_1 #Class10Probability #BoardExam2025 #NCERTClass10 #MathsSolutions #Class10Preparation #MathsInHindi

This video covers Class 10 Maths Probability Exercise 14.1 NCERT Solutions step by step in Hindi. It will help you understand the concept of probability, solve important NCERT questions, and prepare for Board Exams 2025.

Class 10 Maths Probability

Probability Class 10 NCERT Solutions

Probability Class 10 Exercise 14.1

Class 10 Probability Exercise 14.1 solutions

NCERT Class 10 Probability Questions

Probability Class 10 Explanation in Hindi

Class 10 Probability Important Questions

Probability Class 10 Full Chapter

Class 10 Probability for Board Exam 2025

Probability Class 10 Solutions

Here’s a step-by-step solution guide for NCERT Class 10 Maths, Chapter 14 – Probability, Exercise 14.1:


---

Exercise 14.1 (Probability) Solutions


---

Q1. Complete the statements: (i) Probability of an event that is certain to happen is ___ .
(ii) Probability of an event that is impossible to happen is ___ .
(iii) The probability of an event lies between __ and __ .

✅ Answer:
(i) 1
(ii) 0
(iii) 0 and 1


---

Q2. Which of the following cannot be a probability?
(a) 2/3, (b) –1.5, (c) 15%, (d) 0.7

✅ Answer: (b) –1.5 (because probability cannot be negative or more than 1)


---

Q3. If P(E) = 0.05, what is the probability of ‘not E’?

✅ Answer:
P(E) = 0.05
So, P(not E) = 1 – P(E) = 1 – 0.05 = 0.95


---

Q4. If P(E) = 0.02, what is the probability of (i) an event E happening? (ii) an event E not happening?

✅ Answer:
(i) P(E) = 0.02
(ii) P(not E) = 1 – 0.02 = 0.98


---

Q5. A bag contains lemon flavoured candies only. Malini takes out one candy without looking into the bag. What is the probability that she takes out (i) an orange flavoured candy? (ii) a lemon flavoured candy?

✅ Answer:
(i) Since bag has only lemon candies → Probability of orange candy = 0
(ii) Probability of lemon candy = 1


---

Q6. It is given that in a group of 3 students, the probability of 2 students having the same birthday is 0.008. What is the probability that the 2 students do not have the same birthday?

✅ Answer:
P(same birthday) = 0.008
So, P(not same birthday) = 1 – 0.008 = 0.992


---

Q7. A bag contains a red ball, a blue ball, and a yellow ball. One ball is taken out without looking. What is the probability that the ball taken out is
(i) red? (ii) blue? (iii) yellow?

✅ Answer:
Total balls = 3
So probability of each ball = 1/3

(i) Red = 1/3
(ii) Blue = 1/3
(iii) Yellow = 1/3


---

Q8. A box contains 1 white, 2 red and 3 black balls. One ball is taken at random. What is the probability that the ball taken out is
(i) white? (ii) red? (iii) black?

✅ Answer:
Total balls = 1 + 2 + 3 = 6

(i) White = 1/6
(ii) Red = 2/6 = 1/3
(iii) Black = 3/6 = 1/2


---

Q9. A card is taken out from a well-shuffled deck of 52 cards. Find the probability of getting
(i) a king of red colour
(ii) a face card
(iii) a red face card
(iv) the jack of hearts
(v) a spade
(vi) the queen of diamonds

✅ Answer:
(i) King of red colour → 2 cards (♥, ♦) → 2/52 = 1/26
(ii) Face cards = 12 → 12/52 = 3/13
(iii) Red face cards = 6 (♥, ♦) → 6/52 = 3/26
(iv) Jack of hearts = 1 card → 1/52
(v) Spades = 13 → 13/52 = 1/4
(vi) Queen of diamonds = 1 card → 1/52


---

Q10. A die is thrown once. Find the probability of getting
(i) a prime number
(ii) a number lying between 2 and 6
(iii) an odd number

✅ Answer:
Outcomes on die = {1,2,3,4,5,6}

(i) Prime numbers = {2,3,5} → 3/6 = 1/2
(ii) Numbers between 2 and 6 = {3,4,5} → 3/6 = 1/2
(iii) Odd numbers = {1,3,5} → 3/6 = 1/2