LeetCode problem 232. Implement Queue using Stacks [ 29 Jan 2024 ] 
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📌 Video Overview:
Dive deep into the solution for the LeetCode challenge titled '232. Implement Queue using Stacks'. Whether you're kickstarting your coding journey or aiming for roles at tech giants like Facebook, Amazon, Apple, Netflix, or Google, this tutorial is tailored for you. We'll break down the problem step-by-step, ensuring clarity and understanding.
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A comprehensive walkthrough of the problem statement.
An intuitive explanation for both novice and intermediate coders.
Practical insights for acing interviews with top tech companies.
Code walkthrough to grasp the algorithmic approach.
📌 Chapters:
00:00 Problem Statement
02:28 Example & Approach 1
07:35 Time - Brute Force
12:48 Code - Brute Force Approach
19:02 Approach 2 - Amortized O(1) Time
20:02 Code - Amortized O(1) Time Approach
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Problem Statement : 
Implement a first in first out (FIFO) queue using only two stacks. The implemented queue should support all the functions of a normal queue (push, peek, pop, and empty).
Implement the MyQueue class:
void push(int x) Pushes element x to the back of the queue.
int pop() Removes the element from the front of the queue and returns it.
int peek() Returns the element at the front of the queue.
boolean empty() Returns true if the queue is empty, false otherwise.
Notes:
You must use only standard operations of a stack, which means only push to top, peek/pop from top, size, and is empty operations are valid.
Depending on your language, the stack may not be supported natively. You may simulate a stack using a list or deque (double-ended queue) as long as you use only a stack's standard operations.
 
Example 1:
Input
["MyQueue", "push", "push", "peek", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 1, 1, false]
Explanation
MyQueue myQueue = new MyQueue();
myQueue.push(1); // queue is: [1]
myQueue.push(2); // queue is: [1, 2] (leftmost is front of the queue)
myQueue.peek(); // return 1
myQueue.pop(); // return 1, queue is [2]
myQueue.empty(); // return false
                         
                    
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