Скачать или смотреть 1920. Build Array from Permutation | Leetcode Daily 6 May 2025 | Java | Hindi

"1920. Build Array from Permutation" is a medium-level problem and the LeetCode daily challenge (POTD) for 5 May 2025. The solution, written in Java, is explained with a dry-run on a blackboard, making it accessible to viewers with diverse programming backgrounds by focusing on the logic rather than language-specific details.

Intuition:
The problem asks us to build a new array such that ans[i] = nums[nums[i]] using the original array nums. A naive solution would require creating a new array, thus using extra space. However, we can cleverly modify the original array in-place using a technique that temporarily encodes both the old and new values in each index. The key idea here is to store two values in one integer without losing the original — we take advantage of the fact that all values are in the range 0 to n-1, so multiplying by n lets us shift one value into the higher digits.

During the first loop, we update nums[i] to store both the original value and the desired new value: nums[i] = nums[i] + n * (nums[nums[i]] % n). The modulo ensures we only use the original value (in case nums[nums[i]] was already updated). Then, in the second loop, we divide each element by n to extract just the new value we want, discarding the original. This trick gives us an efficient in-place solution with O(n) time and O(1) extra space, which is a smart and elegant use of number encoding.

Link to the problem: https://leetcode.com/problems/build-a...

Link to the Java Code: https://github.com/AditiChourasia/Lee...

For doubts/queries, please reach out on [email protected]
Connect with me on Linkedin:   / aditi-chourasia-a2a572121  

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