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Скачать или смотреть Solving Verilog's 2's complement Addition and Subtraction Trouble!

  • vlogize
  • 2025-09-03
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Solving Verilog's 2's complement Addition and Subtraction Trouble!
Verilog 2's complement adder/subtractorverilogadditioncalculatorsubtraction
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Описание к видео Solving Verilog's 2's complement Addition and Subtraction Trouble!

Discover how to fix issues with a Verilog 4-bit adder/subtractor, comprehend `two's complement` operations, and effectively display results using a seven-segment display.
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This video is based on the question https://stackoverflow.com/q/64618720/ asked by the user 'Cryptic' ( https://stackoverflow.com/u/14552712/ ) and on the answer https://stackoverflow.com/a/64621971/ provided by the user 'gatecat' ( https://stackoverflow.com/u/10520793/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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Understanding the Issue with Verilog 2's Complement Adder/Subtractor

If you're working with a Verilog-based project that includes a 4-bit adder/subtractor, you may face some challenges, especially when dealing with subtraction involving negative numbers. A common issue arises when performing operations like 5 - 7. Instead of getting a correct result of -2, you might notice that the output is displayed as E, which can be confusing. Let's explore this problem and how to address it effectively.

The Challenge Explained

When you perform 5 - 7 in binary using a 4-bit system, you expect to see a result that reflects -2. However, when represented in two's complement form, -2 is encoded as 1110 in binary. This results in confusion during interpretation, as you've encountered in your project.

Why E Equals -2 in Two's Complement

To clarify, let's break down what happens:

Binary Representation: In a 4-bit interface, the results of operations are limited to just four bits. The hexadecimal representation of 1110 is E, which retains this confusion during digital operations.

Converting Negative to Positive: The mechanism to convert a negative number in two's complement to its positive form is to invert the bits and add 1. Here's how to derive the actual result:

Start with E (which is 1110 in binary):

E in binary: 1110

Invert the bits:

1110 inverted yields 0001

Add 1:

Adding 1 to 0001 gives 0010, which is binary for 2.

This process showcases why your logic may seem incorrect; the representation of numbers in binary can lead to misinterpretations if not managed carefully.

Suggested Corrections in Your Code

To properly implement a functioning 4-bit adder/subtractor using two's complement, consider refining the logic for handling the negative results. Here are some steps you could follow:

Use the Correct Input Handling for s

Ensure that your control signal s effectively determines when to perform subtraction.

You’ve correctly set up XOR operations to achieve this, given that XOR is a straightforward method to toggle bits. However, consider verifying your connections and logic sequence.

Update the Full Adder Logic

It seems the logic in your fullAdder module is generally right, but ensure that the carry propagation is functioning correctly.

Test your inputs with various combinations to ensure accurate summation and subtraction.

Binary Interpretation

Confirm that your outputs align with expected binary-to-decimal conversions, particularly testing your display logic to reflect negative numbers accurately.

Conclusion

Understanding how to navigate the intricacies of two's complement arithmetic in Verilog is crucial for creating a robust adder/subtractor. Remember, an essential part of working with binary numbers is recognizing their representations and how they appear in hexadecimal or decimal forms.

By implementing the suggested corrections and ensuring proper management of control signals and outputs, you should effectively eliminate the issues faced with displaying negative results, allowing for proper interpretation of operations like 5 - 7. Happy coding, and may your Verilog projects be bug-free!

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