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Скачать или смотреть Pair With Given Sum in a Sorted Array | Two Pointer | EASY

  • Gale Praveen
  • 2025-01-06
  • 78
Pair With Given Sum in a Sorted Array | Two Pointer | EASY
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Описание к видео Pair With Given Sum in a Sorted Array | Two Pointer | EASY

Problem Link: https://www.geeksforgeeks.org/problem...

Hey everyone! 👋
In this video, we tackle the problem of finding the number of pairs in a sorted array that sum up to a given target value. 💡 We use an efficient two-pointer technique to solve the problem in linear time.

🔍 What You'll Learn:
Two-pointer approach: We start with two pointers—one at the beginning (left) and the other at the end (right)—to find pairs that sum up to the target value.
Optimized Solution: By leveraging the sorted nature of the array, we can quickly adjust our pointers without having to check every single pair.
Handling duplicates: We'll also learn how to handle duplicate elements to make sure we count distinct pairs with unique indices.

🧑‍💻 How it Works:
We initialize two pointers: left at the start of the array and right at the end.
We check the sum of the elements at the left and right pointers:
If the sum equals the target: We count the pair and then move the pointers inward.
If the sum is less than the target: Move the left pointer to the right (to increase the sum).
If the sum is greater than the target: Move the right pointer to the left (to decrease the sum).
This method ensures that we efficiently find all pairs in a single pass through the array, with a time complexity of O(n)! 💯

📝 Code Walkthrough:
We’ll dive into the C++ code for the countPairs function that implements this approach. The function returns the count of pairs where the sum of their values equals the target.

💻 Why This Approach?
Time-Efficient: Instead of a nested loop (O(n²)), the two-pointer method only takes O(n) time, making it much faster, especially for large arrays!
Easy to Understand: The algorithm is simple and takes advantage of the sorted nature of the array.

🔑 Key Concepts:
Two-pointer technique: Used to reduce the time complexity by narrowing down the search space with each step.
Handling duplicates: We avoid counting the same pair more than once by skipping over duplicate values.
Make sure to like, share, and subscribe for more coding tips and problem-solving tutorials! 🔔

💻 Code & Solution:
Check out the solution code in the pinned comment below.

Don't forget to:
👍 Like this video if you found it helpful!
🔔 Subscribe to the channel for more coding tutorials.
💬 Comment below if you have any questions or doubts — I'll get back to you as soon as possible!

Timestamps:
0:00 - Introduction
3:47 - Observation with Examples (Brute Force)
6:47 - Optimizing through Two Pointer
8:45 - Why Conventional Two Pointer Fails
11:23 - Correcting The Approach
17:32 - Code Walkthrough (Optimised)
19:19 - Time & Space Complexity
20:31 - Thanks For Watching

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