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Скачать или смотреть Understanding Pass-by-Reference in Python Dictionaries: How to Modify Object Values In-Place

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  • 2025-10-11
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Understanding Pass-by-Reference in Python Dictionaries: How to Modify Object Values In-Place
Pass value by reference in dictionarypythondictionarypass by reference
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Описание к видео Understanding Pass-by-Reference in Python Dictionaries: How to Modify Object Values In-Place

Learn how to effectively modify object values stored in Python dictionaries by understanding pass-by-reference techniques.
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This video is based on the question https://stackoverflow.com/q/68711865/ asked by the user 'M G' ( https://stackoverflow.com/u/15030253/ ) and on the answer https://stackoverflow.com/a/68712675/ provided by the user 'S.B' ( https://stackoverflow.com/u/13944524/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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Understanding Pass-by-Reference in Python Dictionaries: How to Modify Object Values In-Place

In Python, dictionaries are powerful data structures that allow you to store and manage data in a key-value format. However, when working with objects, one common question arises: How do you modify the values of an object referenced in a dictionary without copying the value?

The Problem

Suppose you have a class with an instance variable, and you want to store that variable in a dictionary. The catch here is that you want any changes made to the variable to reflect in the dictionary automatically. For example, let’s say you have the following dictionary:

[[See Video to Reveal this Text or Code Snippet]]

You might think that changing self.x would automatically update the value inside foo. However, this is not the case. When you store self.x, what is actually being stored is just its value at that moment. If self.x is 10, then foo actually contains {"a": 10}, which has no inherent link to the actual instance variable.

The Solution

To solve this problem, rather than storing the value itself, you should store a reference to the instance of the object. Here’s how you can do that:

Step-by-Step Example

Define your Class:

Create a class where you'll have an instance variable.

[[See Video to Reveal this Text or Code Snippet]]

Create an Instance:

Instantiate your class to create an object.

[[See Video to Reveal this Text or Code Snippet]]

Store the Instance in a Dictionary:

Instead of storing the value of self.x, store the entire instance of the object.

[[See Video to Reveal this Text or Code Snippet]]

Modify the Instance through the Dictionary:

Now you can modify the instance variable through the dictionary.

[[See Video to Reveal this Text or Code Snippet]]

Output

Running the above code will produce the following output:

[[See Video to Reveal this Text or Code Snippet]]

As shown, the changes made to foo['a'].x are reflected in instance.x, demonstrating that you have effectively modified the object in-place.

Conclusion

In conclusion, the key takeaway is that to alter an object’s properties from a dictionary, you should reference the object itself, not its value. This allows you to maintain a dynamic relationship between the dictionary and the object's instance variables, ensuring that modifications are accurately reflected across your application.

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