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Скачать или смотреть How to Check if an Array Contains Strings from Another Array in JavaScript

  • vlogize
  • 2025-03-27
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How to Check if an Array Contains Strings from Another Array in JavaScript
Check if second array has any string from first arrayjavascript
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Описание к видео How to Check if an Array Contains Strings from Another Array in JavaScript

Discover how to efficiently check if any element in one array is present in another array in `JavaScript`. Follow our step-by-step guide to resolve the problem!
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This video is based on the question https://stackoverflow.com/q/71361406/ asked by the user 'Sonny49' ( https://stackoverflow.com/u/16754494/ ) and on the answer https://stackoverflow.com/a/71361474/ provided by the user 'palmarbg' ( https://stackoverflow.com/u/17783601/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Check if second array has any string from first array

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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How to Check if an Array Contains Strings from Another Array in JavaScript

Have you ever faced a coding challenge where you needed to check if any string from one array appears in another? If you’re using JavaScript, this scenario can often frustrate developers, especially when the solution does not yield the expected results.

In this guide, we will walk through a common problem: determining whether any string from a first array is contained within any string in a second array. We’ll also provide a clear solution and break it down step by step.

The Problem

Suppose you have two arrays:

domainAlertList: A list of specific domains.

search: A list of email addresses.

The goal is to check if any of the strings (domains) from domainAlertList exist in the search array. Here’s what the initial code looks like:

[[See Video to Reveal this Text or Code Snippet]]

Upon running this code, you might notice that it returns false when you expect it to return true. The issue lies in how we are checking for the presence of substrings.

Understanding Why It Fails

The reason the original code does not work is that domainAlertList.includes(r) checks for a direct match between the strings in the two arrays. Since none of the email addresses in the search array match the elements in domainAlertList directly, the function returns false.

The Solution

To fix this, we need to change our approach. Instead of checking for a direct match, we can check if each string in the search array includes any of the strings in the domainAlertList. Here’s how you can implement it:

Updated Function

[[See Video to Reveal this Text or Code Snippet]]

Breakdown of the Code:

Using some() Method:

We utilize the some() method to check if at least one element in the array passes the test implemented by the provided function.

Nested Loops:

The outer some() loops through each domain in domainAlertList.

The inner some() loops through each email in the search array and checks if the email includes the current domain string.

Final Output:

With this nested approach, the function will return true if any string from domainAlertList is found within any of the strings in the search array.

Conclusion

In summary, the key to solving the problem of checking if any string from one array exists in another lies in understanding the difference between direct matches and substring checks. By employing a nested use of the some() method, we can efficiently perform this operation and get the expected results.

Feel free to adapt the solution to suit your specific needs or let us know if you have any questions or further issues!

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