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Скачать или смотреть Resolve the Undefined Issue When Sorting Arrays in JavaScript with sort()

  • vlogize
  • 2025-05-25
  • 1
Resolve the Undefined Issue When Sorting Arrays in JavaScript with sort()
Sorting an Array using .sort in an function equals Undefined in JavaScriptjavascriptarrayssorting
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Описание к видео Resolve the Undefined Issue When Sorting Arrays in JavaScript with sort()

Learn how to properly sort a JavaScript array without modifying the original and avoid returning `undefined` in functions.
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This video is based on the question https://stackoverflow.com/q/69961036/ asked by the user 'HTF Games Studio' ( https://stackoverflow.com/u/17407818/ ) and on the answer https://stackoverflow.com/a/69961081/ provided by the user 'DecPK' ( https://stackoverflow.com/u/9153448/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Sorting an Array using .sort in an function equals Undefined in JavaScript

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Understand How to Sort an Array Without Ending Up with Undefined in JavaScript

Sorting arrays is a common task in programming, especially in JavaScript. However, when you're trying to sort an array within a function and facing an issue with an undefined return value, it can be frustrating. In this post, we will unpack the problem you've encountered and provide you with a clear, step-by-step solution.

The Problem

You are attempting to sort an array of objects representing different species and their number of teeth using the .sort() method. While your function is supposed to return a new sorted array, you discovered it returns undefined instead. Here’s a simplified version of your current function:

[[See Video to Reveal this Text or Code Snippet]]

When you try to log the output with console.log(sortSpeciesByTeeth(speciesArray)), the result is undefined. This is because your function does not explicitly return the sorted array.

The Solution

To create a function that not only sorts an array but also prevents modification of the original array, you can implement two important strategies:

1. Return the Sorted Array

Any time you create a function in JavaScript, you must ensure it returns a value if you want to capture the result outside of the function. The default behavior of a function without a return statement is to return undefined.

2. Use Spread Syntax to Copy the Array

To sort the array without affecting the original, you can use the spread syntax .... This allows you to create a shallow copy of the original array before sorting it.

Here’s how you can modify your function to achieve the desired result:

[[See Video to Reveal this Text or Code Snippet]]

Complete Example

Below is the complete example of how the sorting function works:

[[See Video to Reveal this Text or Code Snippet]]

Why This Works

Sort Method: The sort() method sorts the elements of an array in place but returns the sorted array. By spreading this sorted array, you're creating a new copy without altering the original speciesArray.

Spread Syntax: The spread syntax ... allows you to unpack all elements from the sorted array, ensuring that sortSpeciesByTeeth can return a new sorted array while retaining the order of speciesArray.

Conclusion

By ensuring that your function sortSpeciesByTeeth explicitly returns a value and uses spread syntax, you can sort an array as intended without losing the original data. This way, you resolve the undefined issue and maintain the integrity of your original array. Happy coding!

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