Скачать или смотреть 234. Palindrome Linked List || LeetCode POTD || Explained in HINDI

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In this video, we explore a Java solution to determine whether a linked list is a palindrome.
The isPalindrome method takes the head of a linked list as input and aims to determine whether the list is a palindrome.

The algorithm starts by handling base cases: if the list is empty or has only one node, it is considered a palindrome, and the method returns true.

Next, the algorithm initializes two pointers, slow and fast, both pointing to the head of the list, and a prev pointer initialized to null. It then uses the fast and slow pointer technique to find the middle of the list and reverses the first half of the list in place using the prev pointer.

After reversing the first half of the list, the algorithm compares the reversed first half (prev) with the second half (slow), starting from the middle node. If any nodes mismatch, the list is not a palindrome, and the method returns false. Otherwise, it continues comparing nodes until the end of the list.

Finally, if all nodes match, the method returns true, indicating that the list is a palindrome.

Let n be the number of nodes in the linked list.
The time complexity is O(n), as the algorithm traverses each node of the list once. The space complexity is O(1), as the algorithm uses only a constant amount of extra space regardless of the input size.

Whether you're new to problem-solving or seeking insights into Java programming techniques, this video offers valuable insights into tackling similar challenges effectively.

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