for a positive integer n,let f n theta =(tan theta/2)(1+sectheta)(1+sec 2 theta)...(1+sec 2^ntheta)

Описание к видео for a positive integer n,let f n theta =(tan theta/2)(1+sectheta)(1+sec 2 theta)...(1+sec 2^ntheta)

for a positive integer n, let f n theta = (tan theta/2)(1+sectheta)(1+sec 2 theta)...(1+sec 2^ntheta). then

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