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Скачать или смотреть How to Efficiently Remove Punctuation from Tokenized Text in Python

  • vlogize
  • 2025-05-25
  • 1
How to Efficiently Remove Punctuation from Tokenized Text in Python
Remove punctuation marks from tokenized text using for looppythonfor loopnlpnltkpunctuation
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Описание к видео How to Efficiently Remove Punctuation from Tokenized Text in Python

Discover the easiest way to remove punctuation from tokenized text using a for loop in Python. Get clear guidance and examples to enhance your text processing skills.
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This video is based on the question https://stackoverflow.com/q/69189322/ asked by the user 'Hal' ( https://stackoverflow.com/u/9730443/ ) and on the answer https://stackoverflow.com/a/69189532/ provided by the user 'Nir H.' ( https://stackoverflow.com/u/16911595/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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How to Efficiently Remove Punctuation from Tokenized Text in Python

When working with natural language processing (NLP) in Python, one of the common tasks is to clean your text data by removing unwanted characters, such as punctuation. This can enhance the quality of your text analysis significantly.

However, if you're using a for loop to achieve this, you might have run into a frustrating problem where not all punctuation marks are removed in a single pass. Let's take a closer look at this issue and explore a simple solution that you can implement right away.

Understanding the Problem

Consider the following piece of code that aims to remove punctuation marks from tokenized text:

[[See Video to Reveal this Text or Code Snippet]]

What's Going Wrong?

Your intention is to remove punctuation marks from word_tokens, but you're removing elements from the list that you're currently iterating through. This creates an issue where certain punctuation marks may be skipped during the iteration, resulting in some characters not being removed even after multiple runs of the code.

This happens because, when you modify the list (by removing elements) while iterating over it, the loop may not visit all items in the list as expected.

The Solution

The key to resolving this issue is to iterate over a copy of the list or create a new list altogether, rather than modifying the original list directly. Here's how you can do it:

Method: Using List Slicing

Instead of just assigning w to word_tokens, you should create a full copy of word_tokens using list slicing. Replace your code with the following:

[[See Video to Reveal this Text or Code Snippet]]

Key Points

Slicing: The expression word_tokens[:] creates a shallow copy of the original list. Now w is a separate list containing the same elements as word_tokens but can be modified without affecting the loop.

Efficiency: With this approach, running the code just once will effectively remove all punctuation marks, as you are not altering the list you are iterating over.

Example in Context

Here’s a more complete example that includes the setup:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

By following these simple steps, you can enhance the efficiency of your text processing tasks in Python. Removing punctuation marks from tokenized text should now be a breeze, allowing you to focus on analyzing the content of your text rather than battling with unresponsive loops.

Feel free to adapt and expand upon this method in your own NLP projects. Good luck with your coding journey!

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