Скачать или смотреть Lecture-4 || 350.Intersection of Two Arrays II || Salesforce Interview || Array || Leetcode( PART1)

The LeetCode problem "Intersection of Two Arrays II" requires finding the intersection of two integer arrays, where each element in the result should appear as many times as it shows in both arrays .
Link of the Problem:
https://leetcode.com/problems/interse...

Problem Description:

Given two integer arrays nums1 and nums2, return an array of their intersection. Each element in the result must appear as many times as it shows in both arrays, and you may return the result in any order.

Example:

Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2,2]

Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [4,9]

Your Approach:

To solve this problem, you sorted both arrays and used a two-pointer technique to find their intersection.

Two-Pointer Approach:

1.Sort both arrays: This ensures that equal elements are adjacent, facilitating comparison.

2.Initialize two pointers: Set pointers i and j at the start of nums1 and nums2, respectively.

3.Traverse both arrays:
a.If nums1[i] == nums2[j], add the element to the result and increment both pointers.
b.If nums1[i] Less than nums2[j], increment i.
c.If nums1[i] Greater than nums2[j], increment j.
Continue until one of the pointers reaches the end of its array.

This method efficiently finds the common elements, accounting for duplicates, with a time complexity of O(n log n + m log m) due to the initial sorting, where n and m are the lengths of the input arrays.