Скачать или смотреть CLASS 9 || Exercise 14 (Question 5) || CONSTRUCTION || MATHEMATICS || Ganit prakash ||

This is a step-by-step tutorial for Class 9 Mathematics, covering the Construction chapter (Exercise 14, Question 5) from the Ganit Prakash textbook.
The video demonstrates the advanced construction of:
A Square (ABCD) with a side length of 5 cm.
A Parallelogram (CEFG) that has an area equal to the area of the constructed square, with one angle measuring 60^\circ.
The construction first involves drawing the 5 cm square and extending one side. Next, a 60^\circ angle is constructed at the required vertex, followed by using parallel line properties to complete the final parallelogram. This technique involves creating an intermediate triangle of equal area to the square, a concept that is implied in the steps demonstrated.
Topics Covered: Construction of a Square, Construction of a Parallelogram of Equal Area, 60^\circ Angle Construction.

[00:00] Introduction to the problem (Exercise 14, Question 5: Construct a 5 cm square and an equal area parallelogram with 60^\circ angle).
[00:20] Setting up the base line and constructing the 90^\circ angle.
[01:25] Taking the 5 cm measurement and marking the sides.
[02:18] Completing the construction of the Square ABCD.
[02:44] (Intermediate Step) Drawing the diagonal AC and constructing a point E (implied construction of \triangle ABE of equal area).
[04:17] Identifying the required equal-area triangle (\triangle ABE).
[04:21] Constructing the 60^\circ angle at point C (for the parallelogram).
[04:47] Extending the base line AD and the 60^\circ line.
[05:04] Measuring side CE and cutting the length on the parallel line (completing the parallelogram).
[05:22] Completing the final parallelogram by joining the points.
[05:29] Identifying the required parallelogram CEFG.

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