Prove: i⁡(8⁡-⁡23i)⁡ = ⁡23 + ⁡8⁡i

Complex Numbers: Multiplication of two complex numbers. To prove i(8-23i) = 23 + 8i, take note that i = 0+i, start with the left-hand side members of the given equation. Multiply i to each two terms following the distributive law. Simplify until the right-hand side members of the given equation are obtained.

Take note, imaginary number i = √(-1) or (i^2) = -1.

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