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Скачать или смотреть Mastering SQL: The count(distinct) Command for Nested Group By Queries

  • vlogize
  • 2025-09-25
  • 1
Mastering SQL: The count(distinct) Command for Nested Group By Queries
What is correct syntax for nested group by query?sqlpostgresql
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Описание к видео Mastering SQL: The count(distinct) Command for Nested Group By Queries

Learn how to optimize your SQL queries using the `count(distinct)` syntax to accurately retrieve unique object access counts in nested group by queries.
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This video is based on the question https://stackoverflow.com/q/62758887/ asked by the user 'Ben' ( https://stackoverflow.com/u/5292850/ ) and on the answer https://stackoverflow.com/a/62758931/ provided by the user 'Gordon Linoff' ( https://stackoverflow.com/u/1144035/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

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The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

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Mastering SQL: The count(distinct) Command for Nested Group By Queries

When it comes to analyzing data in SQL, particularly in PostgreSQL, achieving accurate results can often be a challenge. One common problem is determining how many unique entries exist in a specified column, especially when dealing with nested queries and grouping. In this post, we’ll explore the intricacies of nested group by queries and how you can leverage the power of count(distinct) to simplify your SQL code and get the results you need efficiently.

The Problem

Imagine you have a table named auditlog that logs access events. Each entry contains the following columns:

OnDate: The date of the access event

SystemUserId: The identifier for the user accessing the data

ObjectId: The unique identifier for the object being accessed

EntityId: A unique identifier for the entity that the object belongs to

You are tasked with querying how many unique ObjectId values each SystemUserId has accessed, filtered by a specific date range and certain identifiers. Using a straightforward approach with the DISTINCT keyword, you might retrieve a certain number of unique objects for a specific user and entity:

[[See Video to Reveal this Text or Code Snippet]]

However, as you experiment further and attempt to group the results by multiple fields, you encounter a surprising discrepancy in your results. Instead of the expected unique counts, you receive additional duplicates, leading to a total overestimation.

The Solution: Using count(distinct)

Simplifying Your Query

The good news is there’s a cleaner, more efficient way to achieve your goal without the complications of nested queries. Instead of counting occurrences in a subquery and grouping them, you can directly use the count(distinct) function. Here’s how you can rewrite your original query:

[[See Video to Reveal this Text or Code Snippet]]

Breakdown of the Query

Count Distinct Objects: This query effectively counts the distinct ObjectId values associated with each SystemUserId and EntityId.

Date Filtering: It still retains the important conditions for filtering data based on the date range you’re interested in.

Group By Functionality: It groups results by both EntityId and SystemUserId to provide accurate counts per user-entity combination.

Benefits of Using count(distinct)

Clarity: Your query is cleaner and easier to understand.

Efficiency: Avoids the overhead of subqueries that need to compute counts separately before grouping.

Accuracy: Ensures duplicate records don't inflate your counts, leading to accurate reporting.

Conclusion

Using count(distinct) in your SQL queries is a powerful technique that not only simplifies your code but also ensures you receive accurate results without unnecessary complexity. By restructuring your approach to utilize this function, you can analyze access patterns and derive insights from your data more effectively.

In your next SQL query, consider opting for count(distinct) as your go-to solution for unique aggregations—it may very well save you time and headaches in the long run!

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