Скачать или смотреть How to Check Similar Elements in a Java Array and Insert Values

Learn how to check for similar elements in a Java integer array and insert specific values based on their presence.
---
This video is based on the question https://stackoverflow.com/q/67014569/ asked by the user 'Kaarthik' ( https://stackoverflow.com/u/14099218/ ) and on the answer https://stackoverflow.com/a/67015198/ provided by the user 'rlf89' ( https://stackoverflow.com/u/8845767/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: How to check if there are similar elements inside a single integer array and insert new values in Java?

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
---
How to Check Similar Elements in a Java Array and Insert Values

When working with arrays in Java, you might encounter situations where you need to analyze the elements and perform actions based on their properties. One common task is to check if there are similar elements next to each other in an integer array and then insert designated values based on the outcome of that check. In this guide, we will walk through a solution to this problem step-by-step, helping you understand how to approach similar challenges in your own coding projects.

The Problem

You have an integer array, and your goal is to determine whether there are two similar elements next to each other. If they are, you should insert the value 2 into the array. If they are not similar, you should insert the value 1. Your final output should reflect these changes correctly.

To illustrate, consider the input array: [33, 33, 44, 44, 5, 6, 7]. The expected output should be:

[[See Video to Reveal this Text or Code Snippet]]

The Solution

Let’s go through an effective solution implementation step-by-step. We will make use of ArrayList to store the new values dynamically, which provides more flexibility than a standard array.

Step 1: Setup the Array and List

First, you need to create an integer array and an ArrayList to hold the results. The ArrayList allows for dynamic resizing, unlike fixed-size arrays.

[[See Video to Reveal this Text or Code Snippet]]

Step 2: Iterate Over the Array

You will loop through the original array, checking pairs of elements to see if they are similar. If they are similar, you'll add both elements and insert a 2. If they are not similar, you'll add the value 1 instead.

[[See Video to Reveal this Text or Code Snippet]]

Step 3: Handle the Last Element

After the loop, you need to check if the last added item in newList was 1. If so, you will add the last element of the original sample and also add a 1 next to it.

[[See Video to Reveal this Text or Code Snippet]]

Step 4: Output the Result

The last step is to output the resulting list. If you need the results in an array format, you can convert the ArrayList back into an array.

[[See Video to Reveal this Text or Code Snippet]]

This will give you the output:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

This Java program efficiently checks for adjacent similar elements in an integer array and inserts the correct values based on their presence. By using ArrayList, you handle the dynamic nature of array sizes easily. This approach is effective for scenarios with relatively few consecutive similar values.

By following these steps, you'll be better equipped to tackle similar problems in your coding journey. Keep experimenting with different examples to solidify your understanding!