Prove:⁡⁡ (23⁡+⁡8i)/i⁡ = ⁡8 - ⁡23⁡i (Alternate Solution)

Complex Numbers: Division of two complex numbers, an alternate solution to the one example above. To prove (23+8i)/i = 8 - 23i, take note that i = 0+i, start with the left-hand side members of the given equation, split it into two individual fractions: 23/i + 8i/i = 23/i + 8. Multiply to 23/i, both its numerator and denominator by the conjugate of the denominator, which is -i or (-i)/(-i). Perform multiplications in both numerator and denominator. Simplify until the right-hand side members of the given equation are obtained.

Take note, imaginary number i = √(-1) or (i^2) = -1.

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