Скачать или смотреть Kinematics Shortcut: Acceleration from x = a₀ + a₁t + a₂t² | JEE NEET MHT CET 2025 Physics

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In this 47-second speed concept video, we find the acceleration of a particle when its displacement is given by:

x = a₀ + a₁·t + a₂·t²

Timestamps:
00:00 Problem Statement
00:07 Differentiate displacement to get velocity
00:15 Differentiate velocity to get acceleration
00:35 Final acceleration value

Solution:

Given:
x = a₀ + a₁·t + a₂·t²

Velocity:
v = dx/dt = a₁ + 2a₂·t

Acceleration:
a = dv/dt = 2a₂

Final Answer: 2a₂ (constant acceleration)

MCQ Options:
A. a₁
B. 2a₂
C. a₂
D. a₀

✅ Correct Option: B

Perfect For:
Class 11 & 12 CBSE / State Board Physics
JEE Main & Advanced
NEET Physics Kinematics
NDA, CUET, MHT CET

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